Henry's law constant for solubility of methane in benzene is `4.2xx10` mm hg at a particular constant temperature.at this temperature calculate the solubility of methane at (a) 750 mm Hg (b)840 mm Hg

Explanation

`(K_H)_("benzene")=4.2 xx10^-5` mm Hg
solubility of methane=?
P=750 mm Hg `" "` P=840 mm Hg
according to Henry.s law,
`P=K_H.X_("in solution")`
750 mm Hg =`4.2 xx 10^-5` mm Hg. `x_("in solution")`i.e.,solubility at 750 mm =`178.5 xx 10^5`
similarly at P=840 mm Hg
solubility at 840 mm=`840/(4.2 xx 10^-5)`
`200xx10^-5`
Note , the solubility of a methane in benzene increazes with increaze in pressure at constant temprature.