0.32 g of an organic compound, after heating with fuming nitric acid and barium. Nitrate crystals is a sealed tube game 0.466 g of barium sulphate, Determine the percentage of sulphur in the compound.

Explanation

`{:(,"Weight of the"),(,"organic compound"):}}=0.32g`
Weight of the barium sulphate formed =0.466 g
`BaSO_(4)=s`
1 mol of `BaSO_(4)=1 mol of S`
233 of `BaSO_(4)="32 g of S"`
0.466 of `BaSO_(4)=(32)/(233)xx 0.466" g of S"`
0.32 g of compound contaings `=(32)/(233) xx 0.466"g of S"`
100 g of compound contains `=(32)/(233) xx (0.46)/(0.32) xx 100`
=19.74%