In the electrochemical cell : `Zn|ZnSO_(4) (0.01 M)||CuSO_(4)(1.0M)|Cu`, the emf of this Daniel cell is `E_(1)` . When the concentration of `ZnSO_(4)` is changed to `1.0M` and that `CuSO_(4)` changed to `0.01`M, the emf changes to `E_(2)`. From the followings , which one is the relationship between `E_(1)" and "E_(2)` ?

Options

A. `E_(1) lt E_(2)`
B. `E_(1) gt E_(2)`
C. `E_(2) = 0 uparrowE_(1)`
D. `E_(1) = E_(2)`

Answer

B