Given the standard electrode potentials `K^(+)//K = - 2.93 V, Ag^(+)//Ag = 0.80 V,`
`Mg_(2)^(2+)//Hg = 0.79, Mg^(2+)//Mg = - 2.37 V,`
`Cr^(2+)//Cr = - 0.74 V`.
Arrange these metals in their increasing order of reducing power .

Options

A. `Ag lt Hg lt Cr lt Mg lt K `
B. `K lt Mg lt Cr lt Hg lt Ag`
C. `Hg lt Cr lt Mg lt K lt Ag`
D. `Mg lt Cr lt Hg lt Ag lt K`

Answer

a

Explanation

Lower the reduction potential, more easily it is oxidised and hence greater is its reducing power .