A cell is set up between copper and silver electrodes as `Cu|Cu^(2+)||Ag^(+)|Ag`.
Given : `E_(Cu^(2+)//Cu)^(0) = 0.34 V, E_(Ag^(+)//Ag)^(0) = 0.80 V`.
Calculate the emf of the cell .

Explanation

`Cu|Cu^(2+)||Ag^(+) | Ag `
`E_("cell")^(0) = E_(Ag^(+)/Ag)^(0) - E_(Cu^(2+)//Cu)^(0) `
` = 0.80 - 0.34 = 0.46 V`