Calculate the standard free energy change and maximum work obainable by a galvanic cell, where the cell reaction
`Zn(s) + Cu^(2+)(aq) to Cu(s) + Zn^(2+)(aq) `
Given : `E_(Zn^(2+)//Zn)^(0) = - 0.76 V`,
`E_(Cu^(2+)//Cu)^(0) = 0.34 V, F = 96500 C`

Explanation

The cell is
`Zn|Zn^(2+)||Cu^(2+)|Cu`
` E_("cell")^(0) = 0.34 - (-0.76) `
` = 1.1 V" " (. :. n = 2)`
`DeltaG^(@) = - n FE_("cell")^(0) `
` = - 2xx 96500 xx 1.1 V`
` = - 212300 CV mol^(-1)`
` = - 212300 J mol^(-1)`
(1 CV = 1J)
` = - 212.3 KJ mol^(-1)`
Thus the maximum work that can be obtainable from the cell ` = 212.3 KJ mol^(-1)`.