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When an electron(mass=9.1 xx10^(-31) kg)...

When an electron(`mass=9.1 xx10^(-31) kg`) is sent in electric field of `9.1 xx10^(6) N/C`, the acceleration produced is ………..`m//s^2`.

A

(a) `0.8 xx10^(18)`

B

(b) `1.6 xx 10^(-18)`

C

(c) `3.2 xx 10^(18)`

D

(d) `1.6 xx 10^(18)`

Text Solution

Verified by Experts

The correct Answer is:
D
`F_e = eE`
`:.ma = eE`
`a = (eE)/m`
`= (1.6xx10^-19xx9.1xx10^6)/(9.1xx10^-31)`
`= 1.6 xx10^18`
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