Home
Class 12
PHYSICS
The permittivity of vacuum varepsilon0 e...

The permittivity of vacuum `varepsilon_0` equals :

A

(a) `9 xx 10^9 Nm^2 C^(-2)`

B

(b) `1/(9xx 10^9)C^2 N^(-1) m^(-2)`

C

(c) `1/(9xx 10^9 C^2N^(-1)m^(-2))C^2N^(-1)m^(-2)`

D

(d) `1/(4pixx9xx10^9)C^2N^(-1)m^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The unit of permittivity of free space, epsilon_0 is

The unit of permittivity in free space (epsilon_(0)) is ...................... .

The velocity of electromagnetic radiation in a medium of permittivity epsilon_0 and permeability mu_0 is given by:

If the electric flux entering and leaving a closed surface are 6 xx 10^(6) and 9 xx 10^6 S.I. units respectively, then the charge inside the surface of permittivity of free space epsi_(0) is

The equation for permittivity of medimum is

The relative permittivity of water is ________

The refractive index of a medium of absolute permittivity ( epsi ) and absolute permeability (mu) with respect to vacuum is :

The electrostatic force between two point charges kept at a distance d apart , in a medium varepsilon_r =6 is 0.3 N . The force between them at the same separation in vacuum is