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When a point P lies on the axial line of...

When a point P lies on the axial line of the dipole on the side of the positive charge then the potential is

A

`V=P/(4pi varepsilon_0r^2)`

B

`V=(-P)/(4pi varepsilon_0r^2)`

C

V=0

D

`V=P/(4pivarepsilon_0r^3)`

Text Solution

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The correct Answer is:
A
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