Home
Class 12
PHYSICS
The magnitude of the electric field at a...

The magnitude of the electric field at a point P at a distance of 3 m from a point charge Q is 100 `V m^(-1)`
(i) `Q=4.0 mu C`
(ii) The value Q = `10^(-7)C`
(iii) The value `V= 1.8 xx 10^4V`
(iv) The electric potential at P is `V= 3 xx 10^2 V`
Which of the following statements are correct ?

A

statements (ii) and (iv)

B

statements (iii) and (iv)

C

statements (i) and (ii)

D

statements (i) and (iv) are correct

Text Solution

Verified by Experts

The correct Answer is:
C
`E = Q/(4piepsilon_0r^2)`
`:.Q = 4piepsilon_0r^2E`
`= 1/(9xx10^9)xx(3)^2xx100`
`=10^-7C`
`V = Q/(4piepsilon_0r)`
`= (10^-7xx9xx10^9)/3`
`3 xx10^2V`
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the magnitude of the electric field at a point 4 cm away from a line charge of density 2 xx 10^(-6) C m^(-1) .

A point charge produces an electric field 2 NC^(-1) at a point 0.5 m distant from it. Calculate the value of q.

Find the vector joining the points P(2, 3, 0) and Q(-1, -2, -4) directed from P to Q

Consider a point charge +q placed at the origin and another point charge -2p placed at a distance of 9 m from the charge +q . Determine the point between the two charges at which electric potential is zero.

The electric potential at a point (x,y,z) is given by V=-x^2y-xz^3+4 .The electric field vecE at the point is:

Two point charges q_(1) and q_(2) of magnitude + 10^(-8) c and -10^(-8) c respectively are placed 0.1 m apart calculate the electric field between the point charges

A charge Q is uniformly distributed over a large plastic plate. The electric field at a point P close to the centre of the plate is 10V m^(-1) . If the plastic plate is replaced by a copper plate of the same geometrical dimension and carrying the same charge Q the electric field at the point P will become