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The equivalent capacitance of two capati...

The equivalent capacitance of two capatitors in series is `1.5 mu F`. The capacitance of one of them is `4 mu F`. The value of capacitance of the other is

A

`2.4 mu F`

B

`0.24 mu F`

C

`0.417 mu F`

D

`4.17 mu F`

Text Solution

Verified by Experts

The correct Answer is:
A
`1/C_s = 1/C_1+1/C_2`
`1/1.5 = 1/4 + 1/c_2`
`:.C_2 = 24muF`
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