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An electric dipole of charges 2 xx 10^-6...

An electric dipole of charges `2 xx 10^-6C, -2xx10^-6C` are separated by a distance 1 cm. Calculate theelectric field due to dipole at a point on its. (i) axial line 1 m from its centre (ii) equatorial line 1 m from its cnetre.

Text Solution

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Charge `q_1=2xx10^-6C,q_2=-2xx10^-6C,`
Distance od separation r = 1 cm = `10^-2` m.
Electric field due to dipole at a point on the axial line is
`E= 1/(4piepsilon_0)(2p)/r^3,P=qxx2d`
Electric field due to dipole at a point on the equatorial line is
`E= 1/(4piepsilon_0)xxP/r^3`
Electric field due to dipole at a point on the axial line
`E= 1/(4piepsilon_0)(2P)/r^3`
`P= qxx2d= 2xx10^-6xx 10^-2`
`= 2xx 10^-8`
`E= (9xx10^9xx2xx2xx10^-8)/1^3`
`= 36 xx 10^1 = 360NC^-1`.
Electric field at a point 1 m from its centre on the equatorial line is
`E= 1/(4piepsilon_0r^3)`
`P= qxx2d= 2xx10^-6xx 1xx 10^-2`
`= 2xx 10^-8`
`E= (9xx10^9xx2xx10^-8)/1^3`
`= xx 10^1 = 180N^+C^-1`.
Electric field along axial line `= 360 NC^-1`
Electric field along equatorial line `= 180 NC^-1`.
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