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A parallel plate capacitor consists of t...

A parallel plate capacitor consists of two identical circular plates of radius 3 cm which are separated by 2.5mm. Calulate the capacitance. What will be its capacitance if the separation is reduced to half the initial value?

Text Solution

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Radius of each plate
`r=3cm=3xx10^-2m`
`:.` Area of each plate
`A=pir^2`
`=pi(3xx10^-2)^2`
`=28.27xx10^-2m^T2`
Distance between plates
d = 2.5 mm
`=2.5xx10^-3m`
Absolute permittivity of air
`epsilon_0=8.854xx10^-12C^2N^-1m^-2`
Capacitance of the capacitor
`C=(epsilon_0)/d`
`=(8.854xx10^-12xx28.27xx10^-4)/(2.5xx10^-3)`
`= 100xx10^-13 F`
`= 10xx10^-12F`
= 10 pF
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