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How ohm's law is derived form drift velo...

How ohm's law is derived form drift velocity relates current formula ?

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The current flowing through a conductor is,
`I = nAev_d`
But ` v_d = (eE)/m, tau `
`I = nAe (eE)/m , tau `
` I = (n A e^2)/(mL) tau V " "[because E = V/L]`
where V is the potential difference. The quantity `(mL)/(n Ae^2 tau)` is a constant for a given conductor, celled electrical resistance (R).
`I prop V`
The law states that, at a constant temperature, the steady current flowing through a conductor is directly proportional to the potential difference between the two ends of the conductor.
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Knowledge Check

  • For which of the following dependences of drift velocity v_(d) on electric field E, is Ohm's law obeyed?

    A
    `v_(d) prop E`
    B
    `v_(d) prop E^(2)`
    C
    `v_(d) prop sqrt(E )`
    D
    `v_(d)=` constant
  • When current I flows through a wire, the drift velocity of the electrons is v. When current 2I flows through another wire of the same material having double the length and area of cross-section, the drift velocity of the electrons will be

    A
    `(v)/(4)`
    B
    `(v)/(2)`
    C
    v
    D
    2v
  • In a semiconductor (2)/(3) rd of the total current is carried by electrons and remaining (1)/(3) rd by the holes . If at this temperature , the drift velocity of electrons is 3 times that of holes , the ratio of number density of electrons to that of holes is

    A
    a) `(3)/(2)`
    B
    b) `(2)/(3)`
    C
    c) `(5)/(3)`
    D
    d) `(3)/(5)`
  • Similar Questions

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    Two rods are joined end to end as shown. Both have a cross-sectional area of 0.01 cm^2 . Each is 1 m long. One rod is a copper with resistivity of 1.7x10^-6 ohm -centimetre, the other is of iron with a resistivity of 10^-5 ohm-centimeter. How much voltage is required to produce a current of 1 ampere in the rods?

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