Three resistors are connected in series with 10 V supply as shownin the figure. Find the voltage drop across each resistor.

Explanation

`R_1 = 5 Omega, R_2 = 3 Omega, R_3 = 2 Omega, V = 10 ` volt
Effective resistance of series combination,
`R_s = R_1 + R_2 + R_3 = R_s 10 Omega`
`{:("Current"),("in circuit"):}}I = V/R_s = 10 /10 = 1A`
`{:("Voltage drop"),("across"R_1","V_2):}}= IR_1 = 1 xx 5 = 5V`
`{:("Voltage drop"),("across"R_2","V_2):}}= IR_2 = 1 xx 3 = 3V`
`{:("Voltage drop"),("across"R_3","V_3):}}= I3_3 = 1 xx2 = 2V`
Voltage drop across each resistor are ` V_1 = 5 V, V_2 = 3 V, V_3 = 2 V`.