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The mutual inductance between two planar...

The mutual inductance between two planar concentric rings of radii `r_(1)` and `r_(2)(r_(1) > r_(2))` placed in air is given by:

A

`(mu_(0)pir_(1)^(2))/(2r_(2))`

B

`(mu_(0)pir_(2)^(2))/(2r_(1))`

C

`(mu_(0)pir_(2))/(r_(1))`

D

`(mu_(0)pi)/(2)sqrt((r_(1))/(r_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B
`"Magnetic field B"=(mu_(0)I)/(2r_(1))`
Magnetic flux `phi=Bxxpir_(2)^(2)`
`=(mu_(0)I)/(2r_(1))xxpir_(2)^(2)`
But `phi=MI`
`therefore MI=(mu_(0)I)/(2r_(1))xxpir_(2)^(2)`
`therefore MI=(mu_(0)pir_(2)^(2))/(2r_(1))`
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