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The dimension of (1 )/(mu0 epsi0) i...

The dimension of ` (1 )/(mu_0 epsi_0) ` is :

A

`[LT^(-1) ] `

B

`[L^2 T ^(-2) ]`

C

`[L^(-1) T]`

D

`[L^(-2) T^(2) ] `

Text Solution

Verified by Experts

The correct Answer is:
B
` C = (1)/(sqrt(mu_0 epsi_0))`
` therefore (1)/(mu_0 epsi_0) = of C^2 `
` therefore ` Dimensions of
` (1)/(mu_0 epsi _0) ` = Dimension of ` C^2 `
` = [LT^(-1)]^2 `
` = L^2 T^(-2) `
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