Calculate the molar mass of the following compounds.
(a) Urea `(NH_2CONH_2),` (b) Ethanol `(C_2H_5OH),` (c) Boric acid `(H_3BO_3)`
[Atomic mass of N-14, H-1,C-12,B-11,0-16]

Explanation

(a) Urea `(NH_(2)CONH_(2))=2(14)+4(1)+1(16)+1(12)`
=28+4+16+12
=60g
(b) Ethanol `(C_(2)H_(5)OH)=2(12)+6(1)+1(16)`
=24+6+16
=46g
(c) Boric acid `(H_(3)BO_(3))=3(1)+1(11)+3(16)`
=3+11+48
=62g