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A constant force acts on an object of ma...

A constant force acts on an object of mass 10 kg for a duration of 4 s. It increases the objects velocity from `2 ms^(-1) "to" 8 ms^(-1)` . Find the magnitude of the applied force.

Text Solution

Verified by Experts

Mass of an object m = 10 kg
Initial velocity u = `2 ms^(-1)`
Final velocity `v = 8 ms^(-1)`
We know, force F = `(m(v-u))/(t)`
`F = (10(8-2))/(4)`
`= (10xx6)/(4) = 15N`
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