A short bar magnet has a magnetic moment 0.48 J/T. Find the magnitude and direction of the magnetic field produced by the magnet on the axis at a distance of 10 cm from the centre of the magnet.

Explanation

We know that, magnetic field due to a bar magneet a axial positon is
`B = ( mu _(0))/( 4pi) xx ( 2 M )/( r ^(3)) `

where, M is magnetic moment and r is the distnace of the point.
` implies B = ( 10 ^(-7) xx 2 xx 0. 48)/( ( 0.1) ^(3)) = 960 xx 10 ^(-7) T = 9.6 xx 10 ^(-5) T`
The direction of magnetic field from South to North pole.