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A magnet is suspended at angle 30^(@) to...

A magnet is suspended at angle `30^(@)` to the magnetic meridian. Write down the expression for torque acting on the magnet. [Take, magnetic moment as M and magnetic flux density as B]

Text Solution

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Here, Magnetic moment = M
Magnetic flux density =B
Angle between Mand Bis `theta = 30^(@)`
Torque acting on the magnet,
`tau = MB sin 30^(@) = ( MB)/(2)`
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