Velocity of an electromagnetic wave in free space is `v=(1)/(sqrt(mu_(0)epsi_(0)))` where,
`mu_(0)=4pixx10^(-7)N//A^(2)` and `epsi_(0)=(10^(-9))/(36pi)C^(2)//N-m^(2)`. Find the magnitude of v and state what was the outcome of the result?

Explanation

As we know, velocity of light,
`v=(1)/(sqrt(mu_(0)epsi_(0)))`
`=(1)/(sqrt((4pixx10^(-17))xx((10^(-9))/(36pi))))`
`=3xx10^(8)m//s`
The magnitude of v is `3xx10^(8)` m/s which of is equal to the velocity of light.
Light is transverse in nature and its an electromagnetic wave.