Suppose that the electric field amplitude of an electromagnetic wave is `E_(0)=120N//C` and that its frequency is n =50 MHz, what are the values of `omega` and k? What is `(omega)/(k)` for a wave? Find out the value of `(omega)/(k)`. Determine `B_(0)` and `lamda`.

Explanation

As, angular velocity,
`omega=2pin=2xx3.14xx(50xx10^(6))`
`=3.14xx10^(8)rad//s`
Now, propagation vector, `k=(omega)/(c)`
[c is velocity of light or electromagnetic wave]
`impliesk=(3.14xx10^(8))/(3xx10^(8))`
`impliesk=1.05m`
`(omega)/(k)=c=` velocity of light or electromagnetic wave
`(omega)/(k)=` velocity of light or electromagnetic wave
`=3xx10^(8)m//s`
Here, peak value of electric field
`E_(0)=120N//C`
Frequency `n=50NHz=50xx10^(6)Hz`
If `B_(0)` is peak value of magnetic field then we know that,
`(E_(0))/(B_(0))=c" "` [c is velocity of light]
`impliesB_(0)=E_(0)/(c)=(120)/(3xx10^(8))`
`=4xx10^(-7)T` Now, `c=nlamda` [ `lamda` is wavelength of light]
Wavelength of electromagnetic waves
`lamda=(c)/(n)=(3xx10^(8))/(50xx10^(6))=6m`