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The compound which shows metamerism is:...

The compound which shows metamerism is:

A

`C_3H_6O`

B

`C_4H_(10)O`

C

`C_5H_(12)`

D

`C_3H_8O`

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The correct Answer is:
To determine which compound shows metamerism, we first need to understand what metamerism is. Metamerism is a type of isomerism that occurs when two or more compounds have the same molecular formula but differ in the arrangement of alkyl groups around a functional group. This typically occurs in compounds like ketones, ethers, and secondary or tertiary amines. ### Step-by-Step Solution: 1. **Understanding Metamerism**: - Metamerism occurs when there are different alkyl groups on either side of a functional group in a molecule. - For example, in ethers, if we have R-O-R', the R and R' can be different alkyl groups. 2. **Analyzing the Given Options**: - We will evaluate each option to see if it can exhibit metamerism. 3. **Option 1: C3H6O**: - Possible structures: - As an aldehyde: CH3-CH2-CHO (not metameric as CHO is fixed at one end). - As a ketone: CH3-C(=O)-CH3 (not metameric as both sides are the same). - Conclusion: **Does not show metamerism**. 4. **Option 2: C4H10O**: - Possible structures: - As an aldehyde: CH3-CH2-CH2-CHO (not metameric). - As a ketone: CH3-C(=O)-CH2-CH3 (not metameric). - As an ether: CH3-CH2-O-CH2-CH3 (can have variations like CH3-CH2-O-CH3). - Conclusion: **Shows metamerism due to different alkyl groups**. 5. **Option 3: C3H8O**: - Possible structures: - As an aldehyde: CH3-CH2-CHO (not metameric). - As a ketone: CH3-C(=O)-CH3 (not metameric). - As an ether: CH3-O-CH2-CH3 (not metameric). - Conclusion: **Does not show metamerism**. 6. **Final Conclusion**: - The only compound that shows metamerism is **Option 2: C4H10O**.
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