A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution. If this particle were projected with the same speed at an angle `theta` to the horizontal, the maximum height attained by it equals 4R. The angle of projection `theta` is then given by

Options

A. ` theta = sin^-1(( pi^2 R)/(g T^2))^(1/2)`
B. ` theta = sin^-1((2g T^2)/( pi^2 R))^(1/2)`
C. ` theta = cos^-1((2g T^2)/( pi^2 R))^(1/2)`
D. ` theta = cos^-1(( pi^2 R)/(g T^2))^(1/2)`