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A student walks from his house at 6.30 a...

A student walks from his house at 6.30 am and reaches his school at 7:15 am. The distance of the school from his house is 6 km. The speed of the student is

A

`4(1)/(2)` km/h

B

8 km/h

C

6 km/h

D

4 km/h

Text Solution

AI Generated Solution

The correct Answer is:
To find the speed of the student, we can follow these steps: ### Step 1: Determine the total time taken to walk to school The student leaves his house at 6:30 AM and arrives at school at 7:15 AM. - From 6:30 AM to 7:00 AM is 30 minutes. - From 7:00 AM to 7:15 AM is an additional 15 minutes. So, the total time taken is: \[ 30 \text{ minutes} + 15 \text{ minutes} = 45 \text{ minutes} \] ### Step 2: Convert the time from minutes to hours Since speed is usually expressed in kilometers per hour (km/h), we need to convert the time taken into hours. To convert 45 minutes into hours: \[ \text{Time in hours} = \frac{45 \text{ minutes}}{60} = 0.75 \text{ hours} \] ### Step 3: Use the formula for speed The formula for speed is given by: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] ### Step 4: Substitute the values into the formula The distance from the house to the school is 6 km, and the time taken is 0.75 hours. So, substituting the values: \[ \text{Speed} = \frac{6 \text{ km}}{0.75 \text{ hours}} \] ### Step 5: Calculate the speed Now, we perform the calculation: \[ \text{Speed} = \frac{6}{0.75} = 8 \text{ km/h} \] Thus, the speed of the student is **8 kilometers per hour**. ### Summary of the Solution: 1. Total time taken: 45 minutes 2. Time in hours: 0.75 hours 3. Speed formula: Speed = Distance / Time 4. Substitute values: Speed = 6 km / 0.75 hours 5. Calculate speed: Speed = 8 km/h ---
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