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If (16^(2) - 11^(2))^(2//3) = 3^(2) xx A...

If `(16^(2) - 11^(2))^(2//3) = 3^(2) xx A`, then the value of A is

A

`3sqrt(25)`

B

`3sqrt(75)`

C

25

D

5

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AI Generated Solution

The correct Answer is:
To solve the equation \((16^2 - 11^2)^{\frac{2}{3}} = 3^2 \times A\), we will follow these steps: ### Step 1: Calculate \(16^2\) and \(11^2\) First, we need to calculate the squares of 16 and 11. \[ 16^2 = 256 \] \[ 11^2 = 121 \] ### Step 2: Subtract the squares Now, we will subtract \(11^2\) from \(16^2\). \[ 16^2 - 11^2 = 256 - 121 = 135 \] ### Step 3: Raise the result to the power of \(\frac{2}{3}\) Next, we raise the result to the power of \(\frac{2}{3}\). \[ (135)^{\frac{2}{3}} \] ### Step 4: Simplify \(135\) We can express 135 in terms of its prime factors: \[ 135 = 3^3 \times 5 \] ### Step 5: Apply the power to the factors Now we can apply the power of \(\frac{2}{3}\) to the prime factorization: \[ (3^3 \times 5)^{\frac{2}{3}} = (3^3)^{\frac{2}{3}} \times (5)^{\frac{2}{3}} = 3^{3 \times \frac{2}{3}} \times 5^{\frac{2}{3}} = 3^2 \times 5^{\frac{2}{3}} \] ### Step 6: Set the equation equal to \(3^2 \times A\) Now we can set our result equal to \(3^2 \times A\): \[ 3^2 \times 5^{\frac{2}{3}} = 3^2 \times A \] ### Step 7: Cancel \(3^2\) from both sides We can cancel \(3^2\) from both sides of the equation: \[ 5^{\frac{2}{3}} = A \] ### Step 8: Final value of \(A\) Thus, the value of \(A\) is: \[ A = 5^{\frac{2}{3}} \]
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ARIHANT PUBLICATION PUNJAB-SQUARE-SQUARE ROOT AND CUBE-CUBE ROOT-Chapter Exercise
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  7. (1/64)^(0)+(64)^(-1/2)+(32)^(4/5)-(32)^(-4/5)=?

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  8. If 2^(a) = 3^(b) = 6^(-c ), then (1)/(a) + (1)/(b) + (1)/(c ) is equal...

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  11. The value of sqrt(2 + sqrt(3)) + sqrt(2 - sqrt(3)) is

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  13. 4-(2-9)^(0)+3^(2)div1+3 is equal to

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  16. 3 xx 10^(5) + 4 xx 10^(3) + 7 xx 10^(2) + 5 is equal to

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