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(1/64)^(0)+(64)^(-1/2)+(32)^(4/5)-(32)^(...

`(1/64)^(0)+(64)^(-1/2)+(32)^(4/5)-(32)^(-4/5)=?`

A

`17(1)/(5)`

B

`15(1)/(17)`

C

`16(1)/(17)`

D

`17(1)/(16)`

Text Solution

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The correct Answer is:
D
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(1/64)^0+(64)^(-1//2) - (32)^(4//5) is equal to

Evaluate (i) (32)^((1)/(5)) +(-7)^(0) + (64)^((1)/(2)) (ii) (0.00032)^(-(2)/(3)) (iii) ((64)/(125))^(-(2)/(3)) .

simplify (i) (1^(3)+2^(3)+3^(3))^(1/2) (ii) (3/5)^(4)(8/5)^(-12)(32/5)^(6) ,(iii) (1/27)^(-2/3) (vi) [((625)^(-1/2)))^(-1/4)]^(2) ,(v) (9^(1/3)xx27^(-1/2))/(3^(1/6)xx3^(-2/3)) (vi) 64^(-1/3)[64^(1/3)-64^(2/3)] (8^(1/3)xx16^(1/3))/(32^(-1/3)

Find : (i) 64^(1//2) (ii) 32^(1//5) (iii) 125^(1//3)

64^(2/3)xx64^(1/3)xx64^((-5)/3)

The value of:- (i) 64^(1/2) (ii) 32^(1/5) (iii) 125^(1/3) .

Find the value of:- (i) 64^(1/2) (ii) 32^(1/5) (iii) 125^(1/3) .

The value of:- (i) 64^(1/2) (ii) 32^(1/5) (iii) 125^(1/3) .

1+(3+1)(3^(2)+1)(3^(4)+1)(3^(8)+1)(3^(16)+1)(3^(32)+1) is equal to (3^(64)-1)/(2) b.(3^(64)+1)/(2) c.3^(64)-1 d.3^(64)+1

Prove that . (i) [8^(-(2)/(3)) xx 2^((1)/(2))xx 25^(-(5)/(4))] div[32^(-(2)/(5)) xx 125 ^(-(5)/(6)) ] = sqrt(2) (ii) ((64)/(125))^(-(2)/(3)) = (1)/(((256)/(625))^((1)/(4)))+ (sqrt(25))/(root3(64)) = (65)/(16) (iii) [7{(81)^((1)/(4)) +(256)^((1)/(4))}^((1)/(4))]^(4) = 16807 .

ARIHANT PUBLICATION PUNJAB-SQUARE-SQUARE ROOT AND CUBE-CUBE ROOT-Chapter Exercise
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  16. The square of 9 is divided by the cube root of 125. The remainder is

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  17. Which of the following is a perfect square ?

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