Home
Class 14
MATHS
The inner and outer radii of a circular ...

The inner and outer radii of a circular track are respectively 21 m and 28 m. The cost of gravevelling the track at Rs. 5 per sq m is

A

Rs. 1078

B

Rs. 2156

C

Rs. 4312

D

Rs. 5390

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the cost of graveling a circular track with inner and outer radii of 21 m and 28 m respectively, we will follow these steps: ### Step 1: Calculate the area of the outer circle The formula for the area of a circle is given by: \[ \text{Area} = \pi R^2 \] where \( R \) is the radius of the circle. For the outer circle, the radius is 28 m. Using \( \pi \approx \frac{22}{7} \): \[ \text{Area of outer circle} = \pi (28)^2 = \frac{22}{7} \times 28^2 \] Calculating \( 28^2 \): \[ 28^2 = 784 \] Thus, \[ \text{Area of outer circle} = \frac{22}{7} \times 784 \] ### Step 2: Calculate the area of the inner circle Similarly, for the inner circle with a radius of 21 m: \[ \text{Area of inner circle} = \pi (21)^2 = \frac{22}{7} \times 21^2 \] Calculating \( 21^2 \): \[ 21^2 = 441 \] Thus, \[ \text{Area of inner circle} = \frac{22}{7} \times 441 \] ### Step 3: Calculate the area of the graveling The area of the graveling is the area of the outer circle minus the area of the inner circle: \[ \text{Area of graveling} = \text{Area of outer circle} - \text{Area of inner circle} \] Substituting the areas calculated: \[ \text{Area of graveling} = \left(\frac{22}{7} \times 784\right) - \left(\frac{22}{7} \times 441\right) \] Factoring out \( \frac{22}{7} \): \[ \text{Area of graveling} = \frac{22}{7} \times (784 - 441) \] Calculating \( 784 - 441 \): \[ 784 - 441 = 343 \] Thus, \[ \text{Area of graveling} = \frac{22}{7} \times 343 \] ### Step 4: Calculate the area of graveling Now, calculate \( \frac{22}{7} \times 343 \): \[ \text{Area of graveling} = \frac{22 \times 343}{7} \] Calculating \( 22 \times 343 \): \[ 22 \times 343 = 7546 \] Now divide by 7: \[ \text{Area of graveling} = \frac{7546}{7} = 1078 \text{ m}^2 \] ### Step 5: Calculate the cost of graveling The cost of graveling is given as Rs. 5 per square meter. Therefore, the total cost is: \[ \text{Cost} = \text{Area of graveling} \times \text{Cost per sq m} \] Substituting the values: \[ \text{Cost} = 1078 \times 5 = 5390 \text{ Rs} \] ### Final Answer The cost of graveling the track is **Rs. 5390**. ---
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    ARIHANT PUBLICATION PUNJAB|Exercise Chapter Exercise|83 Videos
  • MEASUREMENT SYSTEM

    ARIHANT PUBLICATION PUNJAB|Exercise CHAPTER EXERCISE|111 Videos
  • NUMBER SYSTEM

    ARIHANT PUBLICATION PUNJAB|Exercise Example |33 Videos

Similar Questions

Explore conceptually related problems

The inner and outer radii of a circular track area respectively 21 m and 28 m. The cost of levelling the track at ₹ 5 per sq m is

The inner and outer radius of a circular track are, respectively, 29 m and 23 m. The cost of levelling the track at ₹7/ m^2 is: एक वृत्ताकार पथ की आतंरिक तथा बाहरी त्रिज्या क्रमशः 29 मीटर तथा 23 मीटर है | 7 रुपये प्रति वर्ग मीटर की दर से इस पथ को समतल करवाने की लागत कितनी होगी ?

The inner and the outer radii of a circular track are 7 m and 14 m, respectively. Find the cost of levelling the track at the rate of rs. 100 per m^(2) . The following steps are involved in solving the above problem. Arrange them is sequential order (A) Area of circular track =pi(R^(2)-r^(2)) and given R = 14 m and r = 7 m (B) therefore "Area of circular track"=(22)/(7)(196-49) "(C) Area of the track "=(22)/(7)xx147=22xx21=154cm^(2) (D) "Cost of levelling the path "=462xx100="Rs."46,200

The inner and outer radius of a circular track are 56 m and 63m respectively. Find the area of the track

If the outer and the inner radii of a circular track are 7 m and 3.5 m respectively, then the area of the track is ________.

The outer and inner circumferences of a circular road are 462m and 440m respectively. Find the width of the road.

ARIHANT PUBLICATION PUNJAB-MENSURATION-Chapter Exercise
  1. The length of a rope by which a buffalo must be tethered so that she m...

    Text Solution

    |

  2. The total cost of flooring a room at Rs. 12.50 per m is Rs. 400 . If ...

    Text Solution

    |

  3. The inner and outer radii of a circular track are respectively 21 m an...

    Text Solution

    |

  4. A brick measures 20 cm xx 10 cm xx 7.5 cm . How many bricks will be ...

    Text Solution

    |

  5. A school hall has the dimensions 30 m , 12 m by 6m . Find the number o...

    Text Solution

    |

  6. If the capacity of a cylindrical tank is 1848 m^3 and the diameter of ...

    Text Solution

    |

  7. How many metres of cloth 10 m wide will be required to make a conical ...

    Text Solution

    |

  8. The maxumum number of boxes , each of length 2 m , breadth 4 m and he...

    Text Solution

    |

  9. How many times a wheel of diameter 105 cm wil rotate to covering a dis...

    Text Solution

    |

  10. What will be the semi - perimeter of the following figure ?

    Text Solution

    |

  11. The volume of a cube is 512 cm^(3) . Find the length of its diagonal

    Text Solution

    |

  12. A rectangular grassy plot 160 m by 45 m has a gravel path 3 m wide all...

    Text Solution

    |

  13. If the length and breadth of a rectangle are increased by 10 % and 8 %...

    Text Solution

    |

  14. If the length of a rectangle is increased by 4% and breadth of the rec...

    Text Solution

    |

  15. If sides of a square are increased by 7% , by what percent its area wi...

    Text Solution

    |

  16. If diameter of a circle is decreased by 5% by what percent its area wi...

    Text Solution

    |

  17. If diameter of a circle is increased by 12.5 %, find the percentage in...

    Text Solution

    |

  18. The sides of a triangle are in the ratio 12:15:20: If its perimeter be...

    Text Solution

    |

  19. The side of a square is 5 cm which is 13 cm less than the diameter of ...

    Text Solution

    |

  20. Find the area of a square inscribed in a circle of radius 4 cm.

    Text Solution

    |