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A cone of height 7 cm and base radius 1 cm is curved froma conical block of wood `10 m xx 5 xx 2 ` cm . The percentage wood wastage in the process is `(pi = (22)/(7))`

A

`92 (2)/(3)%`

B

`46 (1)/(3)%`

C

`53 (2)/(3)%`

D

`7(1)/(3)%`

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Calculate the Volume of the Cone The formula for the volume \( V \) of a cone is given by: \[ V = \frac{1}{3} \pi r^2 h \] Where: - \( r \) is the radius of the base of the cone, - \( h \) is the height of the cone. Given: - Radius \( r = 1 \) cm, - Height \( h = 7 \) cm, - \( \pi = \frac{22}{7} \). Substituting the values into the formula: \[ V = \frac{1}{3} \times \frac{22}{7} \times (1)^2 \times 7 \] Calculating this: \[ V = \frac{1}{3} \times \frac{22}{7} \times 1 \times 7 = \frac{22}{3} \text{ cm}^3 \] ### Step 2: Calculate the Volume of the Cuboidal Block The volume \( V \) of a cuboid is given by: \[ V = \text{length} \times \text{width} \times \text{height} \] Given the dimensions of the cuboidal block are \( 10 \text{ m} \times 5 \text{ cm} \times 2 \text{ cm} \). First, we need to convert the length from meters to centimeters: \[ 10 \text{ m} = 1000 \text{ cm} \] Now substituting the values: \[ V = 1000 \text{ cm} \times 5 \text{ cm} \times 2 \text{ cm} = 10000 \text{ cm}^3 \] ### Step 3: Calculate the Wood Wastage The wastage of wood is calculated by subtracting the volume of the cone from the volume of the cuboidal block: \[ \text{Wastage} = \text{Volume of Cuboidal Block} - \text{Volume of Cone} \] Substituting the values we calculated: \[ \text{Wastage} = 10000 \text{ cm}^3 - \frac{22}{3} \text{ cm}^3 \] To perform this subtraction, we convert \( 10000 \) into a fraction with a denominator of \( 3 \): \[ 10000 = \frac{30000}{3} \] Now, substituting this into the wastage formula: \[ \text{Wastage} = \frac{30000}{3} - \frac{22}{3} = \frac{30000 - 22}{3} = \frac{29978}{3} \text{ cm}^3 \] ### Step 4: Calculate the Percentage of Wood Wastage The percentage of wood wastage is given by: \[ \text{Percentage Wastage} = \left( \frac{\text{Wastage}}{\text{Volume of Cuboidal Block}} \right) \times 100\% \] Substituting the values: \[ \text{Percentage Wastage} = \left( \frac{\frac{29978}{3}}{10000} \right) \times 100\% \] Calculating this: \[ = \left( \frac{29978}{30000} \right) \times 100\% \approx 99.926\% \] ### Final Answer The percentage of wood wastage in the process is approximately \( 99.93\% \).
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