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The perimeter of a trapezium is 104 cm, ...

The perimeter of a trapezium is 104 cm, the lengths of its non-parallel sides are 18 cm and 22 cm and its altitude is 16 cm . The area (in ` cm^(2)` ) of the trapezium is

A

1024

B

640

C

512

D

320

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The correct Answer is:
To find the area of the trapezium, we can follow these steps: ### Step 1: Understand the given information We know the following: - Perimeter of the trapezium = 104 cm - Length of non-parallel sides (let's call them L1 and L2) = 18 cm and 22 cm - Altitude (height) of the trapezium = 16 cm ### Step 2: Set up the equation for the perimeter The perimeter of a trapezium is given by the formula: \[ \text{Perimeter} = L1 + L2 + a + b \] where \( a \) and \( b \) are the lengths of the parallel sides. Substituting the known values: \[ 104 = 18 + 22 + a + b \] ### Step 3: Simplify the equation Combine the lengths of the non-parallel sides: \[ 104 = 40 + a + b \] ### Step 4: Solve for the sum of the parallel sides Rearranging the equation gives: \[ a + b = 104 - 40 \] \[ a + b = 64 \] ### Step 5: Use the area formula for the trapezium The area \( A \) of a trapezium can be calculated using the formula: \[ A = \frac{1}{2} \times (a + b) \times \text{height} \] Substituting the values we have: \[ A = \frac{1}{2} \times 64 \times 16 \] ### Step 6: Calculate the area Calculating the area: \[ A = 32 \times 16 \] \[ A = 512 \, \text{cm}^2 \] Thus, the area of the trapezium is \( 512 \, \text{cm}^2 \). ---
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