The initial speed of a runner is 5 m/s and final speed is 25 m/s .the length of track is 100 m . Find the acceleration achieved by the runner .

Options

A. `4.25 m//s^(2)`
B. `2.56 m//s^(2)`
C. `2.87 m//s^(2)`
D. `4.56 m//s^(2)`

Answer

C

Explanation

Given , u = 5 m/s , v = 25 m/s , s = 100 m
Now ,
`v^(2) =u^(2) +2as`
` rArr " " (25)^(2) =(5)^(2) + 2xx a xx 100`
` rArr 625 - 25 = 200 a `
` rArr " " 600/200 = a `
` :. " " a = 3 m//s^(2)` .