100 N force is applied perpendicularly on the surface of `10 cm^(2)` the presence on that surface will be

Options

A. `1xx10^(5) N//m^(2)`
B. `10 xx 10^(5) N//m^(2)`
C. `1xx10^(5) N//m^(2)`
D. `10^(6) N//m^(2)`

Answer

A

Explanation

Given , f = 100 N
`A = 10 cm^(2) = 10/(100 xx 100) = 10^(-3) m^(2)`
` p = F/A = (100 N)/(10^(-3) m^(2)) = 10^(5) N//m^(2)`