There are three bags A, B and C. In each bag there are three types of coloured balls Yellow, Green and Black. In bag A, no. of yellow coloured balls are y and no. of green coloured balls are g. Number of green coloured balls are 4 more than the number of yellow coloured balls. When one ball is picked at random then the probability of getting black colour ball is `(5)/(13)`, The value of y is `18(2)/(11)%` less then g. In bag B, number of yellow coloured balls is `22(2)/(9)%` more than that of bag A. If two balls are picked at random from bag B then the probability of getting both green colour ball is `(4)/(37)`. Total number of balls in bag B is 75. In bag C, the ratio of number of green coloured balls and number of black coloured balls is 7 : 5. Total number of green and black coloured balls is 36. If one ball is picked at random then the probability of getting one yellow ball is `(7)/(13)`.
Difference between the number of green balls in bag A and bag C is how much percent more/less than the sum of the number of black balls in bag A and bag C together?

Options

A. `97.5%`
B. `91%`
C. `75%`
D. `79.5%`