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In the following question two Quantities...

In the following question two Quantities i.e., Quantity I and Quantity II are given. You have to determine the relation between Quantity I and Quantity II.
Given, a, b, c and d are positive integers.
I : `a^(-b)/a^(-a)=a^b xx c`
II : `(a^3xxb^3)/(axxb^2)=(b^3xxd^4)/(db)`
Quantity I: Value of ‘c’
Quantity II: Value of ‘d’

A

Quantity I `gt` Quantity II

B

Quantity I `lt` Quantity II

C

Quantity I `ge` Quantity II

D

Quantity I = Quantity II or no relation can be established

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we will analyze both quantities step by step. ### Step 1: Solve for Quantity I (Value of 'c') The equation given is: \[ \frac{a^{-b}}{a^{-a}} = a^b \cdot c \] Using the property of exponents, we can simplify the left side: \[ \frac{a^{-b}}{a^{-a}} = a^{-b - (-a)} = a^{-b + a} = a^{a - b} \] Now, we equate this to the right side: \[ a^{a - b} = a^b \cdot c \] To isolate \(c\), we can divide both sides by \(a^b\): \[ c = \frac{a^{a - b}}{a^b} = a^{(a - b) - b} = a^{a - 2b} \] Thus, we have: \[ c = a^{a - 2b} \] ### Step 2: Solve for Quantity II (Value of 'd') The equation given is: \[ \frac{a^3 \cdot b^3}{a \cdot b^2} = \frac{b^3 \cdot d^4}{b \cdot d} \] Simplifying the left side: \[ \frac{a^3 \cdot b^3}{a \cdot b^2} = \frac{a^3}{a} \cdot \frac{b^3}{b^2} = a^{3-1} \cdot b^{3-2} = a^2 \cdot b \] Now simplifying the right side: \[ \frac{b^3 \cdot d^4}{b \cdot d} = \frac{b^3}{b} \cdot \frac{d^4}{d} = b^{3-1} \cdot d^{4-1} = b^2 \cdot d^3 \] Now we have: \[ a^2 \cdot b = b^2 \cdot d^3 \] To isolate \(d\), we can rearrange: \[ d^3 = \frac{a^2 \cdot b}{b^2} = \frac{a^2}{b} \] Taking the cube root of both sides gives: \[ d = \sqrt[3]{\frac{a^2}{b}} \] ### Step 3: Compare Quantity I and Quantity II Now we have: - Quantity I: \(c = a^{a - 2b}\) - Quantity II: \(d = \sqrt[3]{\frac{a^2}{b}}\) ### Step 4: Determine the relationship between Quantity I and Quantity II Since \(a\), \(b\), \(c\), and \(d\) are all positive integers, we cannot definitively state a relationship between \(c\) and \(d\) without knowing specific values of \(a\) and \(b\). Therefore, we conclude that there is no definitive relationship between Quantity I and Quantity II. ### Final Answer: There is no relation among them. ---

To solve the given problem, we will analyze both quantities step by step. ### Step 1: Solve for Quantity I (Value of 'c') The equation given is: \[ \frac{a^{-b}}{a^{-a}} = a^b \cdot c \] ...
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