In the following question two equations are given in variables X and Y. You have to solve these equations and determine the relation between X and Y.
`x^2 – 16x + 64 = 0`
`Y^2 = 64`

Options

A. If X `gt` Y
B. If X `lt` Y
C. If `X ge Y`
D. If `X le Y`

Answer

C

Explanation

`6x^2 + 5x + 1 = 0`
`rArr 6x^2 + (3 + 2)x + 1 = 0`
`rArr` 3x(2x + 1) + (2x + 1) = 0
`rArr` (3x + 1)(2x + 1) = 0 `rArr` x = –1/3, –1/2
`4y^2 + 4y + 1 = 0`
`rArr 4y^2 + (2 + 2)y + 1 = 0`
`rArr (2y + 1)^2 = 0`
`rArr` y = –1/2
So, `X ge Y`