What is the uncertainty in the position of electron, if uncertainty in its velocity is 0.006 m/s ?

Explanation

`Delta pi xx Delta v=(h)/(4 pi m)`, therefore, uncertainty in the position, `Delta x=(h)/(4 pi m Delta v)`
`Delta x=(6.626xx10^(-34)kgm^(2)s^(-1))/(4xx3.14xx9.1xx10^(-31)kg xx 0.006 ms^(-1))=0.966xx10^(-2) m`