What is the uncertainty in position of a golfball of mass 40 g and speed 45 m/s if the speed can be measured within an accuracy of 2% ?

Explanation

Uncertainty in velocity, `Delta v=35(2)/(100)=0.7 ms^(-1)`
Therefore, uncertainty in position, `Delta x =(h)/(4 pi m Delta v)=(6.626xx10^(-34) kgm^(2)s^(-1))/(4xx3.14xx(40xx10^(-3)kg)xx0.7 ms^(-1))=1.884xx10^(-33) m`