For an electron in a hydrogen atom, the wave function `psi` is proportional to exp `-r//a_(0)`, where `a_(0)` is the Bohr radius. Find the ratio of probability of finding the electron at the nucleus to the probability of finding it at `a_(0)`.

Explanation

Probability of finding the electron at `s=a_(0)` is proportional to `e^(-2s//s_(0))=e^(-2)`
Since `P= |psi |^(2) prop (e^(-s)//a_(0))^(2)`, probability at nucleus =0