A 1kW radio transmitter operates at a frequency of 880 Hz. How many photons per second does it emit?

Options

A. `1.71xx10^(-21)`
B. `1.71xx10^(33)`
C. `6.02xx10^(23)`
D. `2.85xx10^(28)`

Answer

B

Explanation

For 1k W radio transmitter, the energy is given by `E= nhv =1000 Js^(-1)` Given that `v=880 s^(-1) and h=6.62xx10^(-34) Js`
Substituting in the above equation, we get the number of photons emitted per second
`n=(1000)/((880 s^(-1))xx(6.62xx10^(-34 Js)))=(1000)/(5.831xx10^(-31)) =1.717xx10^(33)`