In an atom, an electron is moving with a speed of `600 ms^(-1)` with an accuracy of 0.005%. Certainty with while the position of the electron can be located is `(h = 6.6xx 10^(-34) kg m^(2)s^(-1))`, mass of electron` m_(e) = 9.1 xx 10^(-31) k`

Options

A. `1.52xx10^(-4) m`
B. `5.10xx10^(-3) m`
C. `1.92xx10^(-3) m`
D. `3.84xx10^(-3) m`

Answer

C

Explanation

Using Heisenberg.s uncertaintiy principle, `Delta x, m Delta v=(h)/(4 pi)" or "Delta x=(h)/(4 pi m Delta v)`
Given that `Delta v=0.005%" of "600 ms^(-1)," so "Delta v=600xx(0.005)/(100)=0.03 ms^(-1)`
Hence, `Delta x =(6.6xx10^(-34))/(4xx3.14xx9.1xx10^(-31)xx0.03)=1.92xx10^(-3) m`