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The orbital angular momentum of an elect...

The orbital angular momentum of an electron in a d-orbital is :

A

`sqrt(6) (h)/(2 pi)`

B

`sqrt(2) (h)/(2 pi)`

C

`(h)/(2 pi)`

D

`(2 h)/(2 pi)`

Text Solution

Verified by Experts

The correct Answer is:
A
Orbital angular momentum `= sqrt(l(l+1)) (h)/(2 pi) =sqrt(2(2+1))(h)/(2 pi) = sqrt(6) (h)/(2 pi)` (Here, l=2, for d-orbitals)
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