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Based on the equation Delta E=-(2.0xx10^...

Based on the equation `Delta E=-(2.0xx10^(-18)J) ((1)/(n_(2)^(2))-(1)/(n_(1)^(2)))` the wavelength of the light that must be absorbed to excite hydrogen electron from level n=1 to level n=2 will be
(Given : `h=6.625xx10^(-34) J s, c=3xx10^(8) ms^(-1)`)

A

`1.325xx10^(-7) m`

B

`1.325xx10^(-10) m`

C

`2.650xx10^(-7) m`

D

`5.300xx10^(-10) m`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta E=-(2.0xx10^(-18) J) ((1)/(n_(2)^(2)-(1)/(n_(1)^(2))))=-(2.0xx10^(-18) J) ((1)/(4)-(1)/(1)) ~~ (2.0xx10^(-18) J) (3//4) =1.5xx10^(-18) J`
`lamda =(hc)/(Delta E) =((6.625xx10^(-34) Js ) (3xx10^(8) ms^(-1)))/((1.5xx10^(-18) J))=1.325xx10^(-7) m`
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