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A atomic masses of He and Ne are 4 and 2...

A atomic masses of He and Ne are 4 and 20 amu respectively. The value of the de Brogile wavelength of He as at `-73^(@)` is ''M'' times that of the de Brogile wavelength of Ne at `727^(@)C`. M is:

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The correct Answer is:
5
The de Broglie wavelength of gas molecules is given as, `lamda =(h)/(sqrt(3 mKT))` where k= Boltzamnn constant
`lamda_(He) = M lamda_(Ne), (h)/(sqrt(3xx4xxkxx200))= M (h)/(sqrt(3xx20xxkxx1000))`
`M =(sqrt(3xx20xxkxx1000))/(sqrt(3xx4xx k xx 200))= sqrt((20xx1000)/(4xx200))= sqrt(25)=5`
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