Equivalent conductivity of 1M` CH_(3)COOH` is `10 Omega^(-1) cm^(2) eq^(-1)` and at infinite dilution `200 Omega^(-1) cm^(2) eq^(-1)` . Hence, percentage ionisation of `CH_(3)`COOH is

Options

A. `5%`
B. `2%`
C. `4%`
D. `1%`

Answer

A

Explanation

`x= (Lamda_(c ))/(Lamda_(0)) = (10)/(200)= 0.05`