The resistance of 0.1 N solution of salt is found to be `2.5 xx 10^(3) Omega` . The equivalent conductance of solution (cell constant = 1.15 `cm^(-1)`) in `Omega^(-1) cm^(2) eq^(-1)` is

Options

A. `3.8`
B. `4.6`
C. `6.4`
D. `7.6`

Answer

B

Explanation

Equivalent conductance `=(100 xx "conductance " xx "cell constant")/("concentration")= 1000 xx (1)/(2.5 xx 10^(3))xx (1.15)/(0.1)= 4.6`