Efficiency of a fuel cell is 80% and the standard heat of reaction is -300 kJ. The reaction involves two electrons in redox change. The `E^(@)`for the cell is:

Options

A. 1.24V
B. 2.48V
C. 0V
D. 0.62V

Answer

A

Explanation

Efficiency `= (Delta G^(@))/(Delta H^(@))= (nE^(@)F)/(Delta H)= 80 therefore E^(@)= - (80 xx (-300) xx 10^(3))/(2 xx 96500 xx 100)= 1.24V`