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A current of 965 ampere is passed for 1 ...

A current of 965 ampere is passed for 1 sec through 1 litre solution of 0.02 N `NiSO_(4)` using Ni electrodes. What is the new concentration of `NiSO_(4)` ?

A

0.01M

B

0.01M

C

0.002M

D

0.02M

Text Solution

Verified by Experts

The correct Answer is:
B
`(w)/(E )= (965 xx 1)/(96500)= 0.01`, equivalent of `NiSO_(4)` present initially `=1 xx 0.02 = 0.02`. If Ni electrodes are used no change in conc. `NiSO_(4)` i.e., 0.02N nor 0.01M
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