Given that `K_(sp)` of CuS= `10^(-35)` and `E_(Cu2+ //Cu)^(@)=0.34 V` The standard oxidation potential of `Cu| Cus|S^(2-)` half cell is ………….

Options

A. 1.0V
B. 0.693V
C. `-0.690V`
D. `-1.0V`

Answer

B

Explanation

`Cu^(2+) (aq) + 2e rarr Cu(s)`
`ul(Cu(s)+ S^(2-) (aq) rarr CuS(s) + 2e)`
`Cu^(2+)(aq) + S^(2-) (aq) rarr Cus`
`E_(Cu//CuS//S^(2-) = E_(Cu//Cu^(2+)) - (0.059)/(2) log K_(sp)= - 0.34 - (0.059)/(2) log 10^(-35) = -0.34 + 1.0325= 0.693V`