Cost of electricity for the production of xL `H_(2)` at NTP at cathode is x, then cost of production of x L `O_(2)` at NTP at anode will be: (assume 1 mole of electrons as one unit of electricity)

Options

A. 2x
B. 4x
C. 16x
D. 32x

Answer

A

Explanation

`("Volume of " H_(2))/("Volume of " O_(2))= ("Equivalent volume of " H_(2))/("Equivalent volume of " O_(2)), (x)/("Volume of " O_(2))= (11.2)/(5.6)=2`, Volume of `O_(2)= (x)/(2)`. Thus `(x)/(2) LO_(2)` requires x for its production ie., `x LO_(2)` will require 2x for its product